3x^2+5=1-3x+1

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Solution for 3x^2+5=1-3x+1 equation: 



3x^2+5=1-3x+1

We move all terms to the left:

3x^2+5-(1-3x+1)=0

We add all the numbers together, and all the variables

3x^2-(-3x+2)+5=0

We get rid of parentheses

3x^2+3x-2+5=0

We add all the numbers together, and all the variables

3x^2+3x+3=0

a = 3; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·3·3
Δ = -27
Delta is less than zero, so there is no solution for the equation

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